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Area of a parallelogram. The area of a parallelogram ABCD can be found by calculating area of two triangles ABD and triangle BCD. In $\Delta$ADB , $Sin\theta = \cfrac{P_1}{AD}\;\Rightarrow AD=BC=\cfrac{P_1}{Sin\theta}$ $$ $$ In $\Delta$BCD , $Sin\theta =\cfrac{P_2}{DC}\;\Rightarrow DC=AB=\cfrac{P_2}{Sin\theta}$ $\therefore$ Area ABCD = $2.(\cfrac{1}{2}.AB.AD.Sin\theta)$ […]

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