Area of a parallelogram. The area of a parallelogram ABCD can be found by calculating area of two triangles ABD and triangle BCD. In $\Delta$ADB , $Sin\theta = \cfrac{P_1}{AD}\;\Rightarrow AD=BC=\cfrac{P_1}{Sin\theta}$ $$ $$ In $\Delta$BCD , $Sin\theta =\cfrac{P_2}{DC}\;\Rightarrow DC=AB=\cfrac{P_2}{Sin\theta}$ $\therefore$ Area ABCD = $2.(\cfrac{1}{2}.AB.AD.Sin\theta)$ […]

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Read MoreWhat is a parabola Parabola is a conic section defined as, Locus of a point which moves such that its distance from a fixed point is always in a constant ratio to its perpendicular distance from a fixed line, is called a conic section. $$\frac{PS}{PM}=e\,\,\,\,\,(Constant)$$ where ‘e’ is called as eccentricity of conic section , […]

Read MoreThe solution of by-quadratic equation of degree 4 , such that in the product of two of linear factor and other linear factor , Coefficient of x square and x will remains same

Read MoreDistribution of ‘n’ identical objects into ‘m’ numbers of distinct groups. PODCAST ON DISTRIBUTION OF OBJECTS INTO GROUPS Let us consider distribution of n identical objects to m numbers of distinct groups. let $\,x_i \,$ is the number of identical object objects in $i^{th}\, $ group. Therefore $x_1\,+\,x_2\,+\,x_3……….\,+\,x_m\,=\,n\,\,\, ;\,\,\, where\,\, 0\leq x_i\leq n \,,\,\,\, \forall […]

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